A spring stretches 8 cm when a 4 N force is applied. How far will it stretch with a 6 N force? (Hooke's Law: F = kx)
Answer
12 cm
How to solve it
1
Find k: 4 = k × 8, k = 0.5 N/cm
2
New stretch: 6 = 0.5 × x, x = 12 cm
Hints
First find the spring constant k
Then use it to find the new stretch